-16x^2+60x=9x

Solution for -16x^2+60x=9x equation:

-16x^2+60x=9x

We move all terms to the left:

-16x^2+60x-(9x)=0

We add all the numbers together, and all the variables

-16x^2+51x=0

a = -16; b = 51; c = 0;
Δ = b2-4ac
Δ = 512-4·(-16)·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-51}{2*-16}=\frac{-102}{-32}
=3+3/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+51}{2*-16}=\frac{0}{-32}
=0
$